y^2+80y+1120=0

Solution for y^2+80y+1120=0 equation:

y^2+80y+1120=0

a = 1; b = 80; c = +1120;
Δ = b2-4ac
Δ = 802-4·1·1120
Δ = 1920
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1920}=\sqrt{64*30}=\sqrt{64}*\sqrt{30}=8\sqrt{30}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-8\sqrt{30}}{2*1}=\frac{-80-8\sqrt{30}}{2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+8\sqrt{30}}{2*1}=\frac{-80+8\sqrt{30}}{2}
$